Grade 10 — Term 2
10 study notes · 300 practice questions · Aligned with NIE syllabus
Counted in the Idasara Academy app, which you open with a free account. The free notes, revision, practice and library pages for each lesson are linked below.
This term in the Idasara Academy app has 10 lessons (NIE Units 11, 12, 13, 14, 15, 16, 17, 18, 19, 20). For each lesson, this page gives you the points you must know and one exam-style question with its answer. None of it needs an account.
Is this what my class is doing now?
Maybe not. The Idasara app groups lessons into its own terms, and your school may teach them in a different order. Where we know a lesson's NIE unit, it is shown on the lesson. Find the unit your class is on, and start there.
Lessons in This Term
LCM of Algebraic Expressions
What you must know
- HCF vs LCM confusion: Highest Common Factor (HCF) takes common factors with LOWEST powers; LCM takes ALL factors with HIGHEST powers.
- Factorise binomials first: Before finding LCM of (x² - 4) and (x + 2)², factorise them into (x - 2)(x + 2) and (x + 2)²; LCM is (x - 2)(x + 2)².
- Leave LCM in factored form: In Paper 1 Part A, it is standard practice to leave the algebraic LCM in factorised form; do not waste time expanding brackets.
Try one question
Find the Least Common Multiple (LCM) of the algebraic expressions: 4x²y, 6xy³, and 8x³y².
- A. 12x³y³
- B. 24x²y
- C. 48x²y²
- D. 24x³y³
Show the answer
Answer: D. 24x³y³. Numerical coefficients: LCM of 4, 6, 8 is 24. For algebraic powers, take the highest power of each variable: highest power of x is x³; highest power of y is y³. LCM = 24x³y³.
A model question written by Idasara on the exam pattern. It is not from a past paper.
Algebraic Fractions
What you must know
- The illegal cancellation blunder: In (x + 2) / (x + 5), NEVER cancel the x's; terms separated by + or - cannot be cancelled individually.
- Sign change trap in subtraction: In (a/b) - ((c - d)/e), the negative sign applies to the ENTIRE numerator: - (c - d) = -c + d.
- Restricted denominator values: Algebraic fractions are undefined when the denominator equals zero (e.g., 3 / (x - 2) is undefined when x = 2).
Try one question
Simplify the sum of algebraic fractions: 3/(2x) + 5/(3x).
- A. 19/(6x)
- B. 15/(6x²)
- C. 19/(5x)
- D. 8/(5x)
Show the answer
Answer: A. 19/(6x). Common denominator is LCM(2x, 3x) = 6x. 3/(2x) = 9/(6x), and 5/(3x) = 10/(6x). Sum = (9 + 10) / (6x) = 19/(6x).
A model question written by Idasara on the exam pattern. It is not from a past paper.
Percentages
What you must know
- Cost Price vs Selling Price baseline trap: Profit and loss percentages MUST be calculated against Cost Price, NEVER against Selling Price (unless explicitly requested).
- Quarterly rates division: Remember that municipal rates are paid in 4 equal quarterly instalments; divide the annual rate by 4 to find the quarterly payment.
- Time in years for simple interest: If time is given in months, divide by 12 (e.g., 9 months = 9/12 = 3/4 years).
Try one question
A trader buys a television for Rs. 50,000 and sells it at a profit of 15%. What is the selling price of the television?
- A. Rs. 55,000
- B. Rs. 57,500
- C. Rs. 60,000
- D. Rs. 58,000
Show the answer
Answer: B. Rs. 57,500. Profit amount = 15% of 50,000 = (15/100) × 50,000 = Rs. 7,500. Selling Price = Cost Price + Profit = 50,000 + 7,500 = Rs. 57,500.
A model question written by Idasara on the exam pattern. It is not from a past paper.
Equations
What you must know
- Sign-checking in elimination: If matching coefficients have IDENTICAL signs, SUBTRACT the equations; if they have OPPOSITE signs, ADD the equations.
- Verification step: Always substitute your calculated values of x and y back into BOTH original equations to confirm they satisfy both.
- Do not stop at finding x: A frequent error in Paper 1 Part B is finding x and forgetting to substitute back to calculate y and state contextual quantities.
Parallelograms I
What you must know
- Sufficient conditions to prove a quadrilateral is a parallelogram: Show ONE pair of opposite sides is BOTH equal and parallel, OR both pairs of opposite sides are equal, OR diagonals bisect each other.
- Formal geometric citations: When using parallelogram properties in riders, cite 'opp. sides of //gram =', 'opp. angles of //gram =', or 'diagonals of //gram bisect'.
- Consecutive interior angles: Remember that consecutive angles add up to 180° because they are allied (co-interior) angles between parallel lines.
Try one question
In a parallelogram ABCD, angle A = 70°. Find the magnitude of angle B.
- A. 90°
- B. 140°
- C. 70°
- D. 110°
Show the answer
Answer: D. 110°. In a parallelogram, adjacent (consecutive) interior angles between parallel lines are allied/supplementary (sum to 180°). Therefore, angle B = 180° - 70° = 110°.
A model question written by Idasara on the exam pattern. It is not from a past paper.
Parallelograms II
What you must know
- Rhombus diagonal properties: The diagonals of a rhombus meet at 90°, creating four congruent right-angled triangles; this enables applying Pythagoras' theorem to find side length from diagonals.
- Rectangle diagonals vs Rhombus diagonals: Rectangle diagonals are EQUAL but not perpendicular; rhombus diagonals are PERPENDICULAR but not equal in length.
- Proving a figure is a square: First prove it is a rectangle, then prove adjacent sides are equal (or diagonals are perpendicular).
Try one question
Which of the following conditions is sufficient to prove that a quadrilateral is a parallelogram?
- A. The diagonals are perpendicular to each other.
- B. Two adjacent sides are equal in length.
- C. One pair of opposite sides is both equal and parallel.
- D. One pair of opposite angles is equal.
Show the answer
Answer: C. One pair of opposite sides is both equal and parallel.. By theorem, a quadrilateral is a parallelogram if one pair of opposite sides is both equal in length and parallel to each other.
A model question written by Idasara on the exam pattern. It is not from a past paper.
Sets
What you must know
- The double-counting trap: In word problems, 'students who like tea' includes those who like BOTH tea and coffee; students who like ONLY tea = n(A) - n(A ∩ B).
- Venn diagram region labelling: Fill the intersection region n(A ∩ B) first before populating the 'only' crescent regions.
- Outside the circles region: Never forget elements belonging to neither set: n((A ∪ B)') = n(ε) - n(A ∪ B).
Try one question
In a class of 40 students, 25 study Science, 20 study Commerce, and 5 study neither subject. How many students study both subjects?
- A. 15
- B. 10
- C. 5
- D. 12
Show the answer
Answer: B. 10. Total in union n(S ∪ C) = 40 - 5 = 35. By principle of inclusion-exclusion: n(S ∩ C) = n(S) + n(C) - n(S ∪ C) = 25 + 20 - 35 = 45 - 35 = 10.
A model question written by Idasara on the exam pattern. It is not from a past paper.
Logarithms I
What you must know
- The pseudo-distributive logarithm error: log(x + y) NEVER equals log x + log y; similarly log(x - y) NEVER equals log x - log y.
- Quotient law vs fraction of logs: log(x / y) = log x - log y, which is completely different from (log x) / (log y).
- Converting between forms: Master switching rapidly between index form (2⁵ = 32) and log form (log₂ 32 = 5) for Paper 1 Part A questions.
Try one question
Convert the logarithmic equation log₃(81) = 4 into its equivalent index (exponential) form.
- A. 3⁴ = 81
- B. 4³ = 81
- C. 81³ = 4
- D. 3 × 4 = 81
Show the answer
Answer: A. 3⁴ = 81. By definition of logarithm: log_b(a) = c is equivalent to base^c = a. Here, base is 3, power is 4, and number is 81: 3⁴ = 81.
A model question written by Idasara on the exam pattern. It is not from a past paper.
Logarithms II
What you must know
- Bar notation representation: A negative characteristic is written with a bar over it (e.g., 2̄.4532 = -2 + 0.4532 = -1.5468); never write -2.4532 because mantissa MUST remain positive.
- Subtracting logs with bar numbers: When subtracting a bar number, remember that subtracting a negative becomes an addition: 1.2 - 2̄.5 = 1.2 - (-2 + 0.5) = 1.2 + 2 - 0.5 = 2.7.
- Four-figure table mean differences: Add mean difference values to the main table reading; never subtract mean differences.
Try one question
Given that log₁₀(2) = 0.3010 and log₁₀(3) = 0.4771, calculate the value of log₁₀(18).
- A. 1.5562
- B. 0.7781
- C. 1.2552
- D. 1.0791
Show the answer
Answer: C. 1.2552. 18 = 2 × 3² = 2 × 9. Therefore, log₁₀(18) = log₁₀(2) + 2·log₁₀(3) = 0.3010 + 2(0.4771) = 0.3010 + 0.9542 = 1.2552.
A model question written by Idasara on the exam pattern. It is not from a past paper.
Linear Relationships
What you must know
- Gradient subtraction order consistency: In m = (y₂ - y₁) / (x₂ - x₁), maintain the same point order in numerator and denominator; mixing them flips the gradient sign.
- Positive vs negative gradient: A line sloping upwards from left to right has m > 0; a line sloping downwards has m < 0; horizontal line has m = 0; vertical line has undefined gradient.
- Rearranging to standard form: Before reading off m and c, always rearrange the equation into subject y form: from 2y - 4x = 6 to y = 2x + 3 (m = 2, c = 3).
Try one question
What is the gradient (m) and y-intercept (c) of the straight line represented by 2y - 6x = 8?
- A. m = 3, c = 4
- B. m = -3, c = 4
- C. m = 3, c = 8
- D. m = 6, c = 8
Show the answer
Answer: A. m = 3, c = 4. Rewrite equation in y = mx + c form: 2y = 6x + 8 → y = 3x + 4. Thus, gradient m = 3 and y-intercept c = 4.
A model question written by Idasara on the exam pattern. It is not from a past paper.
Before you sign up
What does it cost?
I already go to a Mathematics tuition class
Then you are paying for Mathematics by the subject. Whether an Idasara plan would cost you less depends on how many classes you go to, so put in your own numbers.
Work it out on the pricing page →